x^2+200x-57600=0

Solution for x^2+200x-57600=0 equation:

x^2+200x-57600=0

a = 1; b = 200; c = -57600;
Δ = b2-4ac
Δ = 2002-4·1·(-57600)
Δ = 270400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{270400}=520$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-520}{2*1}=\frac{-720}{2}
=-360
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+520}{2*1}=\frac{320}{2}
=160
$